You have 90 balls altogether. 20 of them are white, 25 are blue,
27 are red, and 18 are green. Now you will draw a ball one at a
time randomly until you've drawn any of the following: either 11
white, 9 blue, 3 red, or 14 green. What is the minimum number of
balls you have to draw until you are 100% sure that you've gotten
one of the previous combinations?
The most number of balls you could possibly have drawn and failed
is to have drawn 10 whites, 8 blues, 2 reds and 13 greens. That
case is possible when 10+8+2+13=33 balls are drawn. You would
necessarily have more than 10 whites or 8 blues or 2 reds or 13
greens in any other case of drawing 33 balls. That is to say,
any other case when 33 balls have been drawn will be a success.
But even in that extreme case, if you draw one more ball, you
must succeed.
Answer: 34 balls.
Edwin