SOLUTION: Please help me with the solution for this question. A student interviewing at a major company wants to know his chances of getting a job offer. He surveyed 18 alumni that had inter

Question 1046678: Please help me with the solution for this question. A student interviewing at a major company wants to know his chances of getting a job offer. He surveyed 18 alumni that had interviewed with company and found9 of them had received a job offer. construct a 90% confidence interval for the population proportion?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Please help me with the solution for this question. A student interviewing at a major company wants to know his chances of getting a job offer. He surveyed 18 alumni that had interviewed with company and found 9 of them had received a job offer. construct a 90% confidence interval for the population proportion?
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Sample proportion = p-hat = 9/18 = 0.5
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Margin of Error = E = z*sqrt(pq/n) = 1.645*sqrt[0.5*0.5/18] = 0.1938
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90% CI:: (p-hat)-ME < p < (p-hat+ME)
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90% CI: 0.5-0.1938 < p < 0.5+0.1938
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90% CI: 0.3062 < 0.6938
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Cheers,
Stan H.
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