SOLUTION: A horse race has 11 entries and one person owns 4 of those horses. Assuming that there are no​ ties,
What is the probability that those four horses finish first, second,
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Question 1045266: A horse race has 11 entries and one person owns 4 of those horses. Assuming that there are no ties,
What is the probability that those four horses finish first, second, third, and fourth?(regardless of order)(Round to four decimal places as needed.)
Found 2 solutions by robertb, ikleyn:
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
"Problems are best solved by those who created them." --robertb
Answer by ikleyn(52788) (Show Source): You can put this solution on YOUR website!
.
As I understand the condition (not very clear presented for those who is unfamiliar with the horse races),
the space of outcomes is the set of combinations of 4 horses of 11.
The number of such combinations is = 11*10*3 = 330.
The probability to have one specific combination of 330 is .
For combinations, see the lesson
- Introduction to Combinations
- PROOF of the formula on the number of Combinations
- Problems on Combinations
in this site.
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