SOLUTION: A sample of the hourly wages of employees who work in a restaurant in Siem Reap has the mean of $5.02 and a standard deviation of $0.09. Using the Chebyshev's Theorem, find the ran

Algebra.Com
Question 1041007: A sample of the hourly wages of employees who work in a restaurant in Siem Reap has the mean of $5.02 and a standard deviation of $0.09. Using the Chebyshev's Theorem, find the range in which at least 75% of the date values fall.
Answer by robertb(5830)   (Show Source): You can put this solution on YOUR website!
Chebyshev's Theorem:
==>
Letting k = 2,
==>
==>
==>
==> the range in which at least 75% of the values fall is the interval
[4.84, 5.20].

RELATED QUESTIONS

The hourly wages of a sample of 18 employees of a medical company are summarized in the... (answered by stanbon,Mathtut,lauranne)
A union of restaurant and foodservice workers would like to estimate the mean hourly... (answered by stanbon)
The average hourly wage(in dollars) for a sample 36 employees at a factory id $10.67 and... (answered by rothauserc)
1:a production department has 35 similar milling machines.the number of breakdown on each (answered by Boreal)
All 5 members of a family work. Their hourly wages (in dollars) are 19, 24, 16, 29, 7... (answered by Cromlix)
All 5 members of a family work. Their hourly wages in dollars are..14,8,25,28,30.... (answered by Boreal)
a preliminary study of hourly wages paid to unskilled employees in three metropolitian... (answered by stanbon)
A union of restaurant and foodservice workers would like to estimate this year's mean... (answered by stanbon)
The hourly rate of janitors in a city had a mean of $15 and standard deviation rate of $3 (answered by stanbon)