SOLUTION: A 90% confidence interval around the variance was calculated. For n = 27 , the confidence interval was 35.0–88.4. Give the variance of the sample.
Algebra.Com
Question 1040407: A 90% confidence interval around the variance was calculated. For n = 27 , the confidence interval was 35.0–88.4. Give the variance of the sample.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A 90% confidence interval around the variance was calculated. For n = 27 , the confidence interval was 35.0–88.4. Give the variance of the sample.
-----
The width of the CI is 2*ME
-----
Your Problem::
2*ME = (88.4-35) = 53.4
ME = 26.7
--------------
ME = z*s/sqrt(n)
26.7 = 1.645*s/sqrt(27)
----
1.645*s = 26.7*sqrt(27) = 138.74
s = 84.34
Ans: variance = s^2 = 84.34^2 = 7113.23
-----------
Cheers,
Stan H.
----------
RELATED QUESTIONS
A 90% confidence interval around the variance was calculated. For n=27, the confidence... (answered by stanbon)
A 90% confidence interval around the variance was calculated. For n=27, the confidence... (answered by stanbon)
What is the 90% confidence interval for the variance of exam scores for 28 algebra... (answered by robertb)
Find the following critical values used in a(n) 88% confidence interval for a population... (answered by Boreal)
construct a 99% confidence interval for the true proportion if n=60 and... (answered by stanbon)
Construct the confidence interval for the population. mean c = 0.90; x = 8.6 , sigma =... (answered by Boreal)
Construct the confidence interval for the population mean u.
c= 0.98, x =7.4, s =0.5, n= (answered by Theo,ewatrrr)
Same computed a 90% confidence interval for U (mean of population) from a specific random (answered by stanbon)
construct the confidence interval for the population mean C=90, X= 15.1, S = 8.0, N=... (answered by stanbon)