SOLUTION: A study is designed to investigate whether there is a difference in response to various treatments in patients with rheumatoid arthritis. The outcome is patient's self-reported eff

Algebra.Com
Question 1039865: A study is designed to investigate whether there is a difference in response to various treatments in patients with rheumatoid arthritis. The outcome is patient's self-reported effect of treatment. The data are shown below. Is there a statistically significant difference in the proportions of patients who show improvement between treatments 1 and 2. Apply the test at a 5% level of significance.
Treatment 1: 22 symptoms worsened-14 no effect-14 symptoms improved.
Treatment 2: 14 symptoms worsened-15 no effect-21 symptoms improved.
I need the critical value and the computed statistic. I got 17.3 and 26.7 which are both wrong but I don't know why.
The second half of this question is: based on the above figures (which I got wrong), Which of the following is or are true statement(s)?
A. There is significant evidence, alpha 0.05, to show that there is a difference in the proportion of patients who show improvement between treatments 1 and 2.
B. There is Not significant evidence, alpha 0.05 to show that there is a difference in the proportion of patients who show improvements between treatments 1 and 2.
C. There is significant evidence, alpha 0.05, to show that there is NO difference in the proportions of patients who show improvements between treatments 1 and 2.
D. Both A and C are correct.
I keep getting this whole problem wrong. Please help if you can as I need to understand how to do these and judge whether they are significant or not. My book in not really that helpful.

Answer by jim_thompson5910(35256)   (Show Source): You can put this solution on YOUR website!


Variables used
x1 = number of people who improved under treatment 1
p1 = population proportion of patients who improve under treatment 1
phat1 = sample proportion of patients who improve under treatment 1
n1 = sample size of treatment 1

x2 = number of people who improved under treatment 2
p2 = population proportion of patients who improve under treatment 2
phat2 = sample proportion of patients who improve under treatment 2
n2 = sample size of treatment 2

qhat = average of phat1 and phat2

alpha = 0.05 is the significance level


The hypothesis are
Null:
H0:
Alternate:
H1:

This is a two tailed test. The rule is that if the test statistic is between the two critical values, then we do not reject the null. If the test statistic is not between the two critical values, then we reject H0.


------------------------------------------------------

Treatment 1: 14 patients show improvement
so x1 = 14
This is out of 22+14+14 = 50 total
14/50 = 0.28 = 28% of patients show improvement for treatment 1
phat1 = 0.28

Treatment 2: 21 patients show improvement
so x2 = 21
This is out of 14+15+21 = 50 total
21/50 = 0.42 = 42% of patients show improvement for treatment 2
phat2 = 0.42


The sample sizes of each treatment group is 50, so
n1 = 50
n2 = 50


------------------------------------------------------
Let's find the "average" sample proportion value and call this qhat

qhat = (x1+x2)/(n1+n2)
qhat = (14+21)/(50+50)
qhat = 0.35 .... use a calculator here
------------------------------------------------------

Using that value of qhat, we can compute the standard error

SE = sqrt(qhat*(1-qhat)*(1/n1 + 1/n2))
SE = sqrt(0.35*(1-0.35)*(1/50 + 1/50))
SE = 0.0953939201417 .... use a calculator here


-------------------------------------------------------


Now onto the test statistic

z = (phat1-phat2)/(SE)
z = (0.28 - 0.42)/(0.0953939201417)
z = -1.4675987714106
z = -1.47 ... rounding to two decimal places

-------------------------------------------------------

The level of significance is 5%. Alpha = 0.05
confidence level = 1 - alpha
confidence level = 1 - 0.05
confidence level = 0.95
confidence level = 95%


Use a table like this one to find the critical values. Look at the bottom of the page. Locate the 95% confidence level. Look directly above it and you'll see the value 1.960

Since this is a two-tailed test, this means the critical values are -1.960 and 1.960

------------------------------------------------

Go back to the rule stated above. Since -1.47 is definitely between -1.960 and 1.960, this means we do not reject the null. We must conclude that p1 = p2. There isn't significant evidence to prove it wrong.

So the final answer is
B. There is Not significant evidence, alpha 0.05 to show that there is a difference in the proportion of patients who show improvements between treatments 1 and 2.

Further reading:
https://onlinecourses.science.psu.edu/stat414/node/268


RELATED QUESTIONS

A migraine is a particularly painful type of headache, which patients sometimes wish to... (answered by Boreal)
An experiment is designed to investigate the impact of different positions of the mother... (answered by donovan1)
A study was to investigate the oral status of a group of patients diagnosed with... (answered by proyaop)
2. N Hill et al conducted a clinical study to compare the standard treatment for head... (answered by stanbon)
Using the data below, suppose we focus on the proportions of patients who show... (answered by CPhill)
A study was conducted to investigate the effectiveness of hypnotism in reducing pain.... (answered by Boreal)
In a sample of 100 Republicans, 72 favored the president’s anti - drug program; while (answered by ikleyn)
In a medical Study patients are classified in 8 ways according to whether they have blood (answered by stanbon)
Records of 40 used passenger cars and 40 used pickup trucks (none used commercially) were (answered by CPhill)