SOLUTION: The average score of 36 teenage boys playing a computer game was 110,000 with a standard deviation of 20,000. What is the 95% confidence interval for the true mean score of all tee

Question 1039845: The average score of 36 teenage boys playing a computer game was 110,000 with a standard deviation of 20,000. What is the 95% confidence interval for the true mean score of all teenage boys?
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
110000+/-t(0.975,df=35)*20000/sqrt(36)
t value is 2.03
95% CI is 110,000+/-2.03(20000)/6=(103,233,116,767)
The formula is t*s/sqrt(n)
Look up the t in the table under 35 (n-1) df, and use 0.05 1 tail/0.025 2-tail which is what this is. The sample size is 36.
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