SOLUTION: In a random sample of 800 refreshment-dispensing machines, it is found that an average of 8.1 ounces is dispensed with a standard deviation of 0.85 ounce.
Find the probability t
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Question 1036402: In a random sample of 800 refreshment-dispensing machines, it is found that an average of 8.1 ounces is dispensed with a standard deviation of 0.85 ounce.
Find the probability that the true mean is between 8.157 and 8.185. Round your answer to the tenths place.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
z(a)=(8.157-8.1)*sqrt(800)/0.85. Using z-value with sample size of 800. Dividing the denominator by the sample size is the same as multiplying it in the numerator.
z=1.89
z(b)=(8.185-8.1)*sqrt(800)/0.85
z=2.83
The probability is 2.7% (the distance between those two z-values.
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