69% of men consider themselves baseball fans. If you
randomly select 10 men and ask each if he considers
himself a pro ball fan find the probability that the
number who consider themselves fans is exactly 5,
On your TI-83 or 84,
Press 2ND VARS
Scroll down to binompdf( [not binomcdf( ]
and press ENTER
It's 10 trials, with p=0.69, the probability of selecting
1 fan in 1 trial, with the x value of 5.
binompdf(10,0.69,5)
press ENTER, read
0.1128377619
at least 6,
Here we have to find the probability of the complement event
and subtract it from 1. That's the probability of 5 or fewer,
so
On your TI-83 or 84,
Press 2ND VARS
This time, scroll down to binomcdf( [not binompdf( ]
and press ENTER
It's 10 trials, with p=0.69, the probability of selecting
1 fan in 1 trial, with the x value of 5.
binomcdf(10,0.69,5)
press ENTER, read
0.1679474597
Subtract from 1,
0.8320525403
and less than 4
That must be interpreted as "3 or less"
On your TI-83 or 84,
Press 2ND VARS
Scroll down to binomcdf( [not binompdf( ]
and press ENTER
It's 10 trials, with p=0.69, the probability of selecting
1 fan in 1 trial, with the x value of 3.
binomcdf(10,0.69,3)
press ENTER, read
0.01286367757
Edwin