SOLUTION: In a recent game the mean score was 200 and the standard deviation was 25.
(a) Find the z-score of Jacob who scored 120.
(b) Find the z-score of Layla who scored 250.
(c) If Nan
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Question 1033548: In a recent game the mean score was 200 and the standard deviation was 25.
(a) Find the z-score of Jacob who scored 120.
(b) Find the z-score of Layla who scored 250.
(c) If Nancy had a z-score of 1.5, what was her score?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
n a recent game the mean score was 200 and the standard deviation was 25.
(a) Find the z-score of Jacob who scored 120.::
Z(120) = (120-200)/25 = -80/25 = -3.2
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(b) Find the z-score of Layla who scored 250.
Z(250) = (250-200)/25 = 2
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(c) If Nancy had a z-score of 1.5, what was her score?
X = Z*S + Mean
X = 1.5*25 + 200
X = 237.50
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Cheers,
Stan H.
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