SOLUTION: The lengths of pregnancies in a small rural village are Normally distributed with a mean of 263 days and a standard deviation of 14 days.
What percentage of pregnancies last few
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Question 1032356: The lengths of pregnancies in a small rural village are Normally distributed with a mean of 263 days and a standard deviation of 14 days.
What percentage of pregnancies last fewer than 252 days?
P(X < 252)
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The lengths of pregnancies in a small rural village are Normally distributed with a mean of 263 days and a standard deviation of 14 days.
What percentage of pregnancies last fewer than 252 days?
P(X < 252)
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z(252) = (252-263)/14 = -11/14
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P(x < 252) = P(z < -11/14) = normalcdf(-100,-11/14) = 0.2160
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Cheers,
Stan H.
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