SOLUTION: I dont understand this problem. Can someone explain it to me and help me give the answer? A disc jockey wants to select 5 songs that contain a CD that contains 13 songs. How m

Question 1028632: I dont understand this problem. Can someone explain it to me and help me give the answer?
A disc jockey wants to select 5 songs that contain a CD that contains 13 songs.
How many 5 song selections are possible? Put your answer in the form [XXXX].
Found 2 solutions by Alan3354, Natolino1983:
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
A disc jockey wants to select 5 songs that contain a CD that contains 13 songs.
How many 5 song selections are possible? Put your answer in the form [XXXX].
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If order does matter, ie, if ABCDE is not the same as ADCEB, and there are no duplicates, then
= 13*12*11*10*9
= 154440
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If order doesn't matter, ie, if ABCDE is the same as ADCEB, and there are no duplicates, then
= 13*12*11*10*9/(5*4*3*2*1)
= 1287
[XXXX]
Answer by Natolino1983(23) (Show Source): You can put this solution on YOUR website!
The songs cannot be repeated, and the order is not important.
So the answers is the combynatory of 13 over 5 = 13!/(13-5)!� 5! = 1287.
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