SOLUTION: A jar contains five red marbles and three green marbles. A marble is drawn at random and not replaced. A second marble is then drawn from the jar. Find the probability that the fir

Question 1027585: A jar contains five red marbles and three green marbles. A marble is drawn at random and not replaced. A second marble is then drawn from the jar. Find the probability that the first marble is red and the second marble is green.

Found 2 solutions by Fombitz, fractalier:
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!

Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Since this is a logical "and" case, we have to multiply the separate events' probabilities...thus
P(red then green) = 5/8 * 3/7 = 15/56
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