SOLUTION: Use the pattern in Pascal's triangle to find the probability of getting 2 heads when four fair coins are tossed. (type an integer or a simplified fraction)

Question 1026474: Use the pattern in Pascal's triangle to find the probability of getting 2 heads when four fair coins are tossed. (type an integer or a simplified fraction)
Found 2 solutions by ikleyn, Timnewman:
Answer by ikleyn(52803) (Show Source): You can put this solution on YOUR website!
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Use the pattern in Pascal's triangle to find the probability of getting 2 heads
when four fair coins are tossed. (type an integer or a simplified fraction)
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It is = = . Here is the binomial coefficient equal to = 6.

Answer by Timnewman(323) (Show Source): You can put this solution on YOUR website!
lets follow your question up by expansion as suggested by pascal using pascals triangle.
In a coin,we have tail (T) and head (H).
Therefore a coin =(H+T)
since there are four coin here,we raise (H+T) to power of 4
That is,(H+T)^4
Expand the above,we have
(H+T)^4=H^4+4H^3T+6H�T�
+HT^3+H^4
Two head lies on 6H�T�
but p(H)=1/2 also, p(T)=1/2
Therefore,
p(two head)=p(6H�T�)
=6(1/2)�(1/2)�
=6(1/4)(1/4)
=6(1/16)
=6/16
=3/8
Hope this helps too?
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