SOLUTION: An urn contains 5 red balls and 3 green balls. A ball is drawn randomly and 6 more of the same color are added to the urn. Then another ball is drawn. Let R1= event ball # is red.

SOLUTION: An urn contains 5 red balls and 3 green balls. A ball is drawn randomly and 6 more of the same color are added to the urn. Then another ball is drawn. Let R1= event ball # is red.

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Question 1026170: An urn contains 5 red balls and 3 green balls. A ball is drawn randomly and 6 more of the same color are added to the urn. Then another ball is drawn. Let R1= event ball # is red. G1= even the ball # is green. Find Pr(R1|R2)
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
P(R1|R2) = P(R1∩R2)/P(R2)
=P(R1∩R2)/(P(R1∩R2)+P(G1∩R2)) =
Note that P(R1∩R2) = P(R2|R1)*P(R1) =
and P(G1∩R2) = P(R2|G1)*P(G1) = .
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