SOLUTION: There are estimates of the margin of error for confidence levels other than 95%. For a 90% confidence level and a sample size of n, the margin of error is approximately 82/ sq ro

Question 1026086: There are estimates of the margin of error for confidence levels other than 95%. For a 90% confidence level and a sample size of n, the margin of error is approximately
82/ sq root of n %
%.
Suppose we wish to have a margin of error of 2% with a 90% confidence level. Approximately how many people should we interview?

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Suppose we wish to have a margin of error of 2% with a 90% confidence level. Approximately how many people should we interview?
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n = [1.645/0.02]^2*(1/2)^2 = 1691 when rounded up
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Cheers,
Stan H.
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