SOLUTION: Suppose A and B are independent events in a sample space S. Given that Pr(A)=1/4 Pr(B)=1/3 Calculate Pr(A&B|AUB) My work: I was able to get A&B to be 1/12 because I multiplied P

Question 1026007: Suppose A and B are independent events in a sample space S. Given that Pr(A)=1/4 Pr(B)=1/3 Calculate Pr(A&B|AUB)
My work: I was able to get A&B to be 1/12 because I multiplied Pr(A) by the Pr(B), however I do not know how to get Pr(AUB). Please help!
Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
Since A and B are independent, P(A&B) = P(A)*P(B) = 1/12.
By the General Addition Law, P(AuB) = P(A) + P(B) - P(A&B) = 1/4 + 1/3 - 1/12 = 1/2.
==> P(A&B|AuB) = P((A&B)&(AuB))/P(AuB) = P(A&B)/P(AuB) =
Note: (A&B)&(AuB) = A&B because A&B is a subset of AuB.
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