SOLUTION: Please please help me on this question! I have no clue how to do it. Raffle tickets numbered 1 through 30 are placed in a box. Tickets for a second raffle numbered 21 to 48 are

Question 1024565: Please please help me on this question! I have no clue how to do it.
Raffle tickets numbered 1 through 30 are placed in a box. Tickets for a second raffle numbered 21 to 48 are placed in another box. One ticket is randomly drawn from each box. What is the probability that both tickets will be greater than 20 or less than 30?
- (28/81)
- (13/10)
- (1/10)
- (361/810)
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
I'm assuming you mean greater than 20 and less than 30.
In the first box, there are 9 tickets (21,22,23,24,25,26,27,28,29) that meet the requirement.
So the probability is,

In the second box, there are also 9 tickets(21,22,23,24,25,26,27,28,29) so that probability is,

These are independent events so,

Well it doesn't match any of the answers.
Please re-check the problem setup and repost.

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