SOLUTION: Assume that the time a computer technician spends responding to a ticket item is normally distributed with a mean of 37 minutes and a standard deviation of 5 minutes. Assume that a

Question 1020638: Assume that the time a computer technician spends responding to a ticket item is normally distributed with a mean of 37 minutes and a standard deviation of 5 minutes. Assume that an outstanding ticket item is chosen at random.
A.Calculate the probability that the response time will be between 30 and 40 minutes.
B.Calculate the probability that the response time will be more than 45 minutes.
C.Calculate the probability that the response time will be less than 32 minutes.
D.Calculate the probability that the response time will be between 40 and 45 minutes.
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
NORMAL Distribution: mean of 37 minutes and a standard deviation of 5 minutes
Using TI Calculator
A.Calculate the probability that the response time will be between 30 and 40 minutes.
The syntax is normalcdf(smaller, larger, �, σ). P = normalcdf(30,40,37,5)
B.Calculate the probability that the response time will be more than 45 minutes.
P = normalcdf(45,9999,37,5) 9999 a placeholder for the larger value to be at least 5 standard deviations from the mean.
C.Calculate the probability that the response time will be less than 32 minutes. P = normalcdf(-9999,32,37,5)
D.Calculate the probability that the response time will be between 40 and 45 minutes.
P = normalcdf(40,45,37,5)
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