SOLUTION: The mode of the positive intergers 3,5,8,10,18,X,Y is 8, and their mean is Y. Find the values of X and Y.

Question 1020228: The mode of the positive intergers 3,5,8,10,18,X,Y is 8, and their mean is Y. Find the values of X and Y.

Answer by robertb(5830) (Show Source): You can put this solution on YOUR website!
Based on the given information, we have
, since y is the mean of the seven positive integers.
<==>
==> 44 + x = 6y
Now since 8 is the mode , and the known values of the data are distinct, either x or y is equal to 8.
If we let x = 8, then the corresponding value of y is 26/3, which is not acceptable.
Hence , and 44 + x = 48 ==> .
RELATED QUESTIONS
The mean of the eight positive intergers (all < 10) 5,8,X,X,6,Y,6,5 is 7. Find the values (answered by robertb)

The mean of the numbers 1,3,X,Y,10,15 where X and Y are positive intergers is 7. Show... (answered by rothauserc)

the mean of 1,2,x,11,y,14 is 8 and the median is 9 find the values of x and... (answered by ewatrrr)

the sum of two number is 18 and their difference is 8. solve the system x+y=18... (answered by ewatrrr)

Given {{{2^x=8^(y+1)}}} and {{{9^y=3^(x-9)}}}, find the values of... (answered by Tatiana_Stebko)

Evaluate the exponential values for three positive values of x, three negative values of... (answered by jim_thompson5910)

If x and y are intergers, find the domain of {(x,y):/y/=x and x (answered by stanbon)
The arithmetic mean of two numbers x and y is the unmber x+y/2. If x and y are rational... (answered by venugopalramana)
3;x;10;y;21 is a quadratic pattern .Calculate the values of x and y (answered by htmentor)