SOLUTION: A single fair die is tossed once. Let Y be the number facing up. Find the expected value and variance of Y
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Question 1018800: A single fair die is tossed once. Let Y be the number facing up. Find the expected value and variance of Y
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
Expected value= x*p(x)
it is (1/6)(1+2+3+4+5+6)=3.5
variance is
sum of (x-mean)^2/n
(1/6)(2.5^2+1.5^2+0.5^2+0.5^2+1.5^2+2.5^2)=
(1/6)*17.50=2.92
E(x)=3.5
V(x)=2.92
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