SOLUTION: If the probability of getting a contract A is 0.25, B is 0.15. What is the probability of a. Getting both contracts b. Getting contract A only c. Getting contract B only d. No

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Question 1018171: If the probability of getting a contract A is 0.25, B is 0.15. What is the probability of
a. Getting both contracts
b. Getting contract A only
c. Getting contract B only
d. Not getting both contracts
e. Not getting at least one contract
Found 2 solutions by FrankM, solver91311:
Answer by FrankM(1040)   (Show Source): You can put this solution on YOUR website!
Answer by solver91311(24713)   (Show Source): You can put this solution on YOUR website!


       A(0.25)       B(0.15)     P(Both)    =  0.0375  [P(A) * P(B)]
                 Not B(0.85)     P(A only)  =  0.2125  [P(A) * P(Not B)]

   Not A(0.75)       B(0.15)     P(B only)  =  0.1125  [P(Not A) * P(B)]
                 Not B(0.85)     P(Neither) =  0.6375  [P(Not A) * P(Not B)]


Part a, b, and c are read directly from the table.

Part d, "Not Both" is 1 minus P(Both) which is the same as P(A only) plus P(B only) plus P(Neither).

Part e, "Not at least one", is the same as P(Neither); see table.


John

My calculator said it, I believe it, that settles it

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