SOLUTION: In a certain town, 75% of the households own a cellular phone, 45% own a laptop and 40% own both a cell phone and a laptop. Determine the probability that a randomly selected per

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Question 1008739: In a certain town, 75% of the households own a cellular phone, 45% own a laptop and 40% own both a cell phone and a laptop.
Determine the probability that a randomly selected person owns a laptop OR a cellular phone?

Answer by fractalier(6550)   (Show Source): You can put this solution on YOUR website!
P(lap or cell) = P(lap) + P(cell) - P(lap and cell)
= .45 + .75 - .40 = .80 = 80%

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