SOLUTION: Let p1 be the proportion of successes in the first population and let p2 be the proportion of successes in the second population. Suppose that you are testing the hypotheses:
H0
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Question 1005606: Let p1 be the proportion of successes in the first population and let p2 be the proportion of successes in the second population. Suppose that you are testing the hypotheses:
H0:p1−p2=0Ha:p1−p2≠0
Futhermore suppose that z∗=1.73, find and input the p-value for this test. Round your answer to 4 decimal places.
To answer the question input only the actual number. Do not include units. Do not give your answer in sentence form -- just include the numerical answer rounded to exactly 4 decimal places.
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
z=1.73 in a two-tailed test.
probability it will be that far from the left is 0.9582
BUT this is a two-tailed test, and the p-value must be doubled.
p=0.0418 for one-tail
p=0.0836 for two-tailed test.
The last is not a sentence, it is a fragment.
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