SOLUTION: A basketball player hits three-point shots 46% of the time. If she takes 4 shots during a game, what is the probability that she misses the first shot and hits the last three shots
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Question 1004750: A basketball player hits three-point shots 46% of the time. If she takes 4 shots during a game, what is the probability that she misses the first shot and hits the last three shots?
Answer by fractalier(6550) (Show Source): You can put this solution on YOUR website!
Multiply the individual shot probabilities...
so we have (for 46% to make it and 54% to miss)...
P = .54*.46*.46*.46 = 0.0526 = 5.26%
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