SOLUTION: A random sample of 100 observations from a population with standard deviation 28.51 yielded a sample mean of 94.9.
1. Given that the null hypothesis is μ=90 and the alterna
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Question 1003538: A random sample of 100 observations from a population with standard deviation 28.51 yielded a sample mean of 94.9.
1. Given that the null hypothesis is μ=90 and the alternative hypothesis is μ>90 using α=.05, find the following:
(a) Test statistic =
(b) P - value:
2. Given that the null hypothesis is μ=90 and the alternative hypothesis is μ≠90 using α=.05, find the following:
(a) Test statistic =
(b) P - value
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A random sample of 100 observations from a population with standard deviation 28.51 yielded a sample mean of 94.9.
1. Given that the null hypothesis is μ=90
and the alternative hypothesis is μ>90 using α=.05, find the following:
(a) Test statistic::
z(94.9) = (94.9-90)/(28.51/sqrt(100) = 1.7190.
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(b) P - value::
P-value = P(z > 1.719 ) = normalcdf(1.719,100) = 0.0428
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2. Given that the null hypothesis is μ=90 and the alternative hypothesis is μ≠90 using α=.05, find the following:
(a) Test statistic::
z(94.9) = 1.719
----------------
(b) P - value::
p-value = 2*P(z > 1.719) = 0.0856
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Cheers,
Stan H.
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