SOLUTION: A box contains 33 parts, of which 3 are defective and 30 are nondefective. 2 parts are selected without replacement.
(1) Find the probability P(both are defective). (Give your
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Question 1000809: A box contains 33 parts, of which 3 are defective and 30 are nondefective. 2 parts are selected without replacement.
(1) Find the probability P(both are defective). (Give your answer correct to two decimal places.)
(2)Find the probability P(exactly one is defective). (Give your answer correct to two decimal places.)
Answer by Fombitz(32388) (Show Source): You can put this solution on YOUR website!
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Since you don't know whether the first part is defective or the second, you count both instances.
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The last remaining probability is neither part is defective.
If you sum all those probabilities, you will get 1, which shows you that these are the only three possible occurences.
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