You can
put this solution on YOUR website!The first thing I would do is draw a picture. Since the Hotel (H) and Airport (A) are each 10 miles from the Conference Center (CC), they are both on a circle of radius 10 centered at the Conference Center. So now look at the question. You want the distance between A and H to be less than the distance between CC and H. But we know the distance between CC and H is 10. So we want the probability that the distance between A and H is less than 10. Both A and H can be at any point on that circle's edge. The circumference of the circle is 2pi*radius, or 20pi miles. If you choose a place on that circle for H, A can be up to 10 miles to the left or 10 miles to the right to be closer than CC. So a total of 20 miles make A and H closer than A and C. The probability of A being within those 20 miles, rather than the rest of the circle, is 20/20pi, or 1/pi, or approximately 31.7%.
