# SOLUTION: Note: Use the five-step hypothesis testing procedure to solve the following exercise. [show the answer for each of the five steps] As part of a study of corporate employee

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 Question 133654: Note: Use the five-step hypothesis testing procedure to solve the following exercise. [show the answer for each of the five steps] As part of a study of corporate employees, the Director of Human Resources for PNC, Inc. wants to compare the distance traveled to work by employees at their office in downtown Cincinnati with the distance for those in downtown Pittsburgh. A sample of 35 Cincinnati employees showed they travel a mean of 370 miles per month, with a standard deviation of 30 miles per month. A sample of 40 Pittsburgh employees showed they travel a mean of 380 miles per month, with a standard deviation of 26 miles per month. At the .05 significance level, is there a difference in the mean number of miles traveled per month between Cincinnati and Pittsburgh employees? Answer by stanbon(60771)   (Show Source): You can put this solution on YOUR website!A sample of 35 Cincinnati employees showed they travel a mean of 370 miles per month, with a standard deviation of 30 miles per month. -------------------- A sample of 40 Pittsburgh employees showed they travel a mean of 380 miles per month, with a standard deviation of 26 miles per month. -------------------- At the .05 significance level, is there a difference in the mean number of miles traveled per month between Cincinnati and Pittsburgh employees? -------------------- Ho: mu(Cin)-mu(Pitt) = 0 Ha: mu(Cin)-mu(Pitt) is not 0 ------------------------------- Run a 2 Sample T Test on your TI caluculator: Test statistic: t = -1.5466 p-value = 0.12627... ---------------------- Conclusion: p-value is greater than alpha = 5%, so Fail to reject Ho. The means are statistically the same. ========================= Cheers, Stan H.