SOLUTION: i did this problem but i dunno if it is correct can you please check it for me
12xy^3-4x^2y^2=
4xy.3y-4xy^2.2=0
4xy^2(3y-N)=0
4xy^2=0
xy^2=01y
xy=0 and y=0
Algebra.Com
Question 99598: i did this problem but i dunno if it is correct can you please check it for me
12xy^3-4x^2y^2=
4xy.3y-4xy^2.2=0
4xy^2(3y-N)=0
4xy^2=0
xy^2=01y
xy=0 and y=0 3y=x
y=x
=3
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
12xy^3-4x^2y^2
= 4xy^2(3y - x)
==================
Cheers,
Stan H.
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