SOLUTION: Can you please help me solve this? Factorise the quadratic expressions using the quadratic formula: x^2-2ax+a^2-b^2 I'm not sure how to change it to a quadratic equation. Tha

Question 985336: Can you please help me solve this?
Factorise the quadratic expressions using the quadratic formula:
x^2-2ax+a^2-b^2
I'm not sure how to change it to a quadratic equation.
Thank you!!
Answer by rothauserc(4718) (Show Source): You can put this solution on YOUR website!
x^2 -2ax +a^2-b^2
the form for the quadratic equation is
ax^2 + bx + c, therefore
*****************************************************************************
for this problem
a = 1
b = -2a
c = a^2-b^2
*****************************************************************************
x = (-b + or - square root(b^2 - 4ac)) / 2a
for this problem
x = (-(-2a) + square root( (-2a)^2 - 4 * (1) * (a^2 - b^2) ) ) / 2
x = ( 2a + square root( 4a^2 - 4a^2 + 4b^2) ) / 2
x = ( 2a + 2b) / 2
x = (a + b)
*****************************************************************************
x = (2a - 2b) / 2
x = (a - b)
therefore the factors are
(x - (a+b)) and (x - (a-b))

RELATED QUESTIONS
I need help expressing the following quadratic expression in factored from by using the... (answered by jim_thompson5910)

Can you please help me solve the following quadratic equation using the quadratic... (answered by Alan3354)

can you help me solve by using the quadratic formula.... (answered by praseenakos@yahoo.com)

Can you help me solve this problem using the quadratic formula? 6x^2 + 3x - 18 =... (answered by stanbon)

please help me solve this problem using the quadratic root formula:... (answered by jim_thompson5910)

Can someone Please, Please, Please help me solve tis problem by using the Quadratic... (answered by jim_thompson5910,JP)

can you help me solve by using the quadratic formula of... (answered by checkley71)

can you help me solve by using the quadratic formula of... (answered by stanbon)

can you help me solve by using the quadratic formula of... (answered by ankor@dixie-net.com)