SOLUTION: Given that x = 1 - 2i is a root of {{{ x^4 - 8x + 23x^2 - 42x +30 }}}, the real solutions to this equation are x = 3 +- sqrt b what is b?

Question 973792: Given that x = 1 - 2i is a root of , the real solutions to this equation are x = 3 +- sqrt b what is b?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Given that x = 1 - 2i is a root of , the real solutions to this equation are x = 3 +- sqrt b what is b?
---------------
If x = 1 - 2i is a root, then 1 + 2i is also a root.
(x^2 - 2x + 5) is the product of the 2 complex roots.
Divide the quartic by that --> a quadratic.
Solve the quadratic.

RELATED QUESTIONS
1. The solution of a polynomial equation are shown below. x = 3+4i x = 5 What is... (answered by josgarithmetic)

The question is: Find all the real and complex zeros of the polynomial... (answered by stanbon)

Given the polynomial function has the given zero, find the other zeros. f(x) = x^3 -... (answered by stanbon)

What is the quadratic equation that has a one root of 1+2i? my work:... (answered by jim_thompson5910,MathTherapy)

Which of the following is the correct solution to the equation x^2-4x+6=0? Explain why... (answered by Alan3354)

find the factors of poly nomial equation of degree greater than 2 A.Give the factored... (answered by MathLover1,MathTherapy)

f(x) = x^3 + (1 - k^2)x + k (a) Show that -k is a root of f. I've already solved this (answered by jsmallt9)

A polynomial P is given a.) Factor P into linear and irreducible quadratic factors with... (answered by stanbon)