SOLUTION: Could someone please walk me though this question? [-24 over 32-8x ] +[ 4x+1 over x^2-7x+ 12] I factored the denominators and got 8(4-x) for the first term and (x-3)(x-4) for t

Question 972549: Could someone please walk me though this question?
[-24 over 32-8x ] +[ 4x+1 over x^2-7x+ 12]
I factored the denominators and got 8(4-x) for the first term and (x-3)(x-4) for the second term but I am not sure what to do after that.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
[-24 over 32-8x ] +[ 4x+1 over x^2-7x+ 12]
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(-24)/(-8(x-4)) + (4x+1)/[(x-4)(x-3)]
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Least common denominator:: -8(x-4)(x-3)
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= [-24(x-3) + (4x+1)(-8)]/[-8(x-4)(x-3)
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= [-24x+72-32x-8]/[-8(x-4)(x-3)]
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= [-56x+64]/[-8(x-4)(x-3)]
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= [7x-8]/[(x-4)(x-3)]
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Cheers,
Stan H.
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