SOLUTION: Solve the following polynomial equation. show your work. x^3+x^2+2x-4=0

Question 970668: Solve the following polynomial equation. show your work.
x^3+x^2+2x-4=0
Answer by Boreal(15235) (Show Source): You can put this solution on YOUR website!
The possible factors are +/- 1 +/-2 and +/-4
Let's try (x-1)
1 ;; 1 ;; 1 ;2 ;;-4
============1 ==2 ;=4
====== 1===2==4==0
(x-1) (x^2+2x+4)=0
One root is 1; the second does not factor (4ac is larger than b^2=see below)
The quadratic formula for the other 2
=[-2 +/- sqrt (4-16)]/2 ;; sqrt (-12)=sqrt (3)* sqrt (-4)= 2i (sqrt (3)
-1 +/- i* sqrt (3)

See a graph of a cubic equation with a root at x=1 and the y-intercept at (0.-4) consistent with the equation
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