SOLUTION: Hey I need help. The problem is the area of a rectangle is given by a polynomial function A(x)=a^2b^2-ab-6. If the length of the rectangle is (ab-3), what would my width be? Show m

Question 961563: Hey I need help. The problem is the area of a rectangle is given by a polynomial function A(x)=a^2b^2-ab-6. If the length of the rectangle is (ab-3), what would my width be? Show me step by step please.
Found 2 solutions by stanbon, MathLover1:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
The problem is the area of a rectangle is given by a polynomial function A(x)=a^2b^2-ab-6. If the length of the rectangle is (ab-3), what would my width be? Show me step by step please.
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(ab)^2 -ab - 6 = (ab-3)(ab+2)
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Width = ab+2
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Cheers,
Stan H.
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Answer by MathLover1(20849) (Show Source): You can put this solution on YOUR website!

the area of a rectangle is given by a polynomial function
....we know that the area of a rectangle is is , so factor completely and see if the is a factor; if it is a factor, then the other part will be the width

....write as
...group

since given that is the length, then is the width

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