SOLUTION: what is the end behavior of h(x) = x^5+4x^2+2 as x approaches negative infinity

Question 959008: what is the end behavior of h(x) = x^5+4x^2+2 as x approaches negative infinity
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
what is the end behavior of h(x) = x^5+4x^2+2 as x approaches negative infinity
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x^5 determines the end behavior.
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As x goes to -oo, x^5 goes to -oo, so the function goes to -oo.
Cheers,
Stan H.
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