SOLUTION:
A rectangular piece of sheet metal has a length that is 2 times its width. In each corner a square with sides of 2.4 inches is cut out. The outer strips are then bent up to fr
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Question 958124:
A rectangular piece of sheet metal has a length that is 2 times its width. In each corner a square with sides of 2.4 inches is cut out. The outer strips are then bent up to from an open box with a volume of 155
in3
. Find the length (in inches) of the original sheet of metal.
Express your answer to three significant digits
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Best to do this completely in variables and substitute the given values last.
u, the side length of the cut out squares;
w, original width
L, original length
v, volume of the open box formed
-
L=2w
u=2.4
v=155
-
Goal is to solve for L and w.
Folding the flaps makes a base area of the box, .
The volume will be the base area multiplied by u.
This is an equation with only one unknown, being w. The other variables are given.
Simplify that equation.
Instead of continuing this completely in symbols, substituting the given values NOW might make the rest of the work, either factoring if possible, or general solution for a quadratic equation, easier to do. Your choice. You take the rest of this. Solve for w, and use the result to evaluate L.
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