SOLUTION: Tutor, Good evening I am have difficulties with this problem could you help me? Solve each of the following quadratic equations. 4x^2 = 13x + 12 I am so confused on

Question 95597This question is from textbook Beginning Algebra
: Tutor,
Good evening I am have difficulties with this problem could you help me?
Solve each of the following quadratic equations.
4x^2 = 13x + 12
I am so confused on how to solve this problem. Thanks in advance for your help. This question is from textbook Beginning Algebra

Found 2 solutions by stanbon, edjones:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Solve each of the following quadratic equations.
4x^2 = 13x + 12
4x^2-13x-12 = 0
Use the quadratic formula to get:
x = [13 +- sqrt(13^2-4*4*-12)]/8
x = [13 +- sqrt(361)]/8
x = [13 +- 19]/8
x = 4 or x = -3/4
=================
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
4x^2-13x-12=0
Quadratic formula:

(13+-(19))/8
x=32/8 and x=-6/8
x=4 and x=-3/4
EdJones
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