SOLUTION: If 2x^2+5x-3=0 and x>0, then what is the value of x? I'm having trouble with the test booklet explanation. It indicates to factor (2x-1)(x-3)=0, but for some reason I am havi

Question 95037: If 2x^2+5x-3=0 and x>0, then what is the value of x?
I'm having trouble with the test booklet explanation.
It indicates to factor (2x-1)(x-3)=0, but for some reason I am having trouble understanding what happens to the 5x. Maybe it is the factoring portion I am drawing a blank on. Please assist me with step by step details. Thank you.
Answer by williacy(2) (Show Source): You can put this solution on YOUR website!
2x^2+5x-3=0
First you must factor 2x^2+5x-3:
1. Multiply the first and last coefficients: 2 x -3 = -6
2. Find two multiples of -6 that can be added to get 5.
3. The two multiples are 6 and -1 {6x-1=-6 and 6+(-1)=5}
4. Use the two multiples to help you write two binomials: (x+6)(x+-1)
5. Since there is a 2 in front of the x^2 term, divide the 6 and -1 by the 2.
6. You will have . . . (x + 3)(x + -1/2)
7. Since you should have all whole numbers and not fractions, take the 2 from the denominator and put it in front of the 2, and thus you will have the factored from of 2x^2+5x-3:
(x + 3)(2x + -1)
Now to solve:
1. Set each of the binomials to equal zero, and solve for x.
x+3 = 0 x = -3
2x + -1 = 0
2x = 1
x = 1/2

RELATED QUESTIONS
6) if m<1=x+30, m<2=x-23, and m<3=2x-7, find x and the value of each numbered angle.... (answered by stanbon)

I'm having issues with these types of problems sinking in. -5x+3=x^2+2x, -5x+3-x^2+2x=0... (answered by josgarithmetic,addingup,ikleyn)

I'm attempting to do corrections on a test, but these three questions are giving me... (answered by stanbon,Edwin McCravy)

I need help with a quadratic problem, I am having trouble with this because it doesn't... (answered by jim_thompson5910)

If {{{ sqrt(x^2-5x-11) +3=x }}} then what value is {{{ x^2-3x+3 }}} ? You have to solve... (answered by mananth)

If {{{ sqrt (x^2-5x-11)+3 = x}}} then what value is {{{ x^2-3x+3 }}}? You have to solve (answered by John10)

y =x2-5x+4 is the question. I am having trouble with table of value. x= 0,1,2,3,4 and... (answered by stanbon)

Hello, I am trying to graph an absolute value equation and cannot seem to solve it. the (answered by jsmallt9)

Im having trouble factoring polynomials: please show the steps and explain (simply)... (answered by lwsshak3)