SOLUTION: Factor the following polynomials completely. 14x² - 20x +6

Algebra.Com
Question 94805: Factor the following polynomials completely.
14x² - 20x +6

Found 2 solutions by checkley71, edjones:
Answer by checkley71(8403)   (Show Source): You can put this solution on YOUR website!
14x^2-20x+6=0
2(7x^2-10x+3)=0
2(7x-3)(x-1)=0
7x-3=0
7x=3
x=3/7 answer.
x-1=0
x=1 answer.

Answer by edjones(8007)   (Show Source): You can put this solution on YOUR website!
All 3 coefficients are divisable by 2, so
we know a lot. Both signs will be the same because there is a + in front of the 3. Both signs will be (-) because of the (-) in front of the 10. Both 7 and 3 are prime numbers so we wont be dividing those up.
2(7x-3)(x-1)This works.
EdJones

RELATED QUESTIONS

Factor each of the following polynomials completely. 14x^2 - 20x + 6 Please help. I (answered by bmauger)
Factor the following polynomial completely. 14x^2 – 20x + 6 (answered by jim_thompson5910)
Factor the following polynomial completely... (answered by elima)
Factor each of the following polynomials completly 14x^2 - 20x +... (answered by prabhjyot)
Factor completely. 14x squared - 20x +... (answered by scott8148,jim_thompson5910)
Factor completely. 14x squared - 20x +... (answered by jim_thompson5910)
factory the following polynomial completely 14x ^2 - 20x +... (answered by Nate)
Hi Everyone, I am supposed to factor the following polynomials completely: (a)... (answered by josmiceli)
Factor each of the following polynomials: 14x^2 - 20x + 6 My answer for this... (answered by checkley75)