From there you can make trials of different combinations, or check Discriminant.
...The discriminant is 100, a perfect square. This indicates that the quadratic factor should be factorable.
(3m____5)(m_____5)
This should work if both constant terms are negative or "subtracted". Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website! I am suppose to factor completely but am unsure how to do
75-60m+12m^2
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12m^2-60m+75=(2m-5)(6m-15) Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website! 75 - 60m + 12m^2
12m^2 - 60m + 75 = 0
12mm - 60m + 75 = 0
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the above quadratic equation is in standard form, with a=12, b=-60 and c=75
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
12 -60 75
into this solver: http://sooeet.com/math/quadratic-equation-solver.php
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the quadratic has two real roots at:
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m = 2.5
m = 2.5
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answer:
(m - 2.5)(m - 2.5)
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now, solve by a different method: completing the square:
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(12mm - 60m + 75 = 0)/12
mm - 5m + 6.25 = 0
mm - 5m + (5/2)(5/2) + 6.25 = (5/2)(5/2)
mm - 5m + (2.5)*(2.5) = (2.5)*(2.5) - 6.25
mm - 5m + (2.5)*(2.5) = 6.25 - 6.25
mm - 5m + (2.5)*(2.5) = 0
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answer:
(m - 2.5)(m - 2.5)
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--- Answer by MathTherapy(10552) (Show Source): You can put this solution on YOUR website!
I am suppose to factor completely but am unsure how to do
75-60m+12m^2
------- Factoring out GCF, 3
3[5(5 - 2m) - 2m(5 - 2m)] , or