SOLUTION: 49x exponent8 - 35x exponent6 - 56x exponent3 over
7x exponent3
Algebra.Com
Question 93710This question is from textbook Beginning Algebra
: 49x exponent8 - 35x exponent6 - 56x exponent3 over
7x exponent3
This question is from textbook Beginning Algebra
Found 2 solutions by Earlsdon, jayanthihemkos@yahoo.com:
Answer by Earlsdon(6294) (Show Source): You can put this solution on YOUR website!
Simplify:
Factor from the numerator.
Cancel the indicated factors.
Answer by jayanthihemkos@yahoo.com(87) (Show Source): You can put this solution on YOUR website!
49x exponent8 - 35x exponent6 - 56x exponent3 over
7x exponent3
49x^8 -35x^6-56x^3/7x^3
Take 7x^3 as common factor
7x^3(7x^5 - 5x^3 - 8)/7x^3
7x^3 in the numerator and denominator is cancelled
7x^5 - 5x^3 - 8
Hence the solution
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