SOLUTION: (x^3+2x^2+x+12)/(x+3)
Algebra.Com
Question 93576: (x^3+2x^2+x+12)/(x+3)
Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Let's simplify this expression using synthetic division
Start with the given expression
First lets find our test zero:
Set the denominator equal to zero
Solve for x.
so our test zero is -3
Now set up the synthetic division table by placing the test zero in the upper left corner and placing the coefficients of the numerator to the right of the test zero.
Start by bringing down the leading coefficient (it is the coefficient with the highest exponent which is 1)
Multiply -3 by 1 and place the product (which is -3) right underneath the second coefficient (which is 2)
Add -3 and 2 to get -1. Place the sum right underneath -3.
Multiply -3 by -1 and place the product (which is 3) right underneath the third coefficient (which is 1)
Add 3 and 1 to get 4. Place the sum right underneath 3.
Multiply -3 by 4 and place the product (which is -12) right underneath the fourth coefficient (which is 12)
Add -12 and 12 to get 0. Place the sum right underneath -12.
Since the last column adds to zero, we have a remainder of zero. This means is a factor of
Now lets look at the bottom row of coefficients:
The first 3 coefficients (1,-1,4) form the quotient
So
You can use this online polynomial division calculator to check your work
RELATED QUESTIONS
x+3=2x+12 (answered by rfer)
divide... (answered by Nate)
Divide... (answered by stanbon)
Divide... (answered by 303795)
Divide x^3+2x^2+x+12/x+3 (answered by 303795)
Divide.... (answered by jim_thompson5910)
Divide... (answered by checkley77)
3^2x +3^x =... (answered by Alan3354)
12-(2x+5)=-2+(x-3) (answered by jim_thompson5910)