SOLUTION: Find the value of p and q if:
(x-3) and (x+1) are factors of x^3+px+q
Where (x-3) I identified the answer as 3p+27+q (Equation 1)
Where (x+1) I identified the answer as -p
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Question 935077: Find the value of p and q if:
(x-3) and (x+1) are factors of x^3+px+q
Where (x-3) I identified the answer as 3p+27+q (Equation 1)
Where (x+1) I identified the answer as -p-1+q (Equation 2)
I thought that I would need to use synthetic division for both factors; then when I had the answer from each I'd use simultaneous equation to solve for one term, substitute it into the equation, then simplify for the second term.
So for p; I thought 4p=28; p=6
and for q; I got utterly lost tbh.
If I substitute the value for p where p=6 into Equation 1; I got q=45
But if I substitute the value for p where p=6 into Equation 2; I got -7.
The book says p=-6 and q=-7
So now I am bewildered where Ive gone wrong
Answer by MathLover1(20850) (Show Source): You can put this solution on YOUR website!
you did this:
identified the answer as .... (Equation 1)
identified the answer as .....(Equation 2)
just solve this system
.... (Equation 1)
.....(Equation 2)
__________________________subtract eq.2 from eq.1
go to eq.2 plug in value for
.....(Equation 2)
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