SOLUTION: Here is a word problem....I always have problems with word problems. The width of a rectangle is 8 feet less than the length. If the area is 20 square feet, find the length

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Let x = the phrase at the end of the first sentence, which is to say,
let x = length.

Then x-8 = width

LW = Area
x(x-8) = 20


x= 10 and x= -2

You must reject the negative value, so the
length x= 10 feet,
width x-8 = 2 feet.

The check of course is that LW= 10*2 = 20 ft^2.

R^2 at SCC