SOLUTION: Here is one that I am stuck on. Actually I have two of them. I might as well give both. 1. Choose the correct factored form for x^

SOLUTION: Here is one that I am stuck on. Actually I have two of them. I might as well give both. 1. Choose the correct factored form for x^ - 12x + 35 I am stuck. Either it is (x +

Question 9337: Here is one that I am stuck on. Actually I have two of them. I might as well give both.
1. Choose the correct factored form for x^ - 12x + 35
I am stuck. Either it is (x + 7)(x + 5) or it is (x - 7)(x - 5)
2. Choose the correct solutions for the quadratic equation x^2 + 3x - 10 + 0.
I believe the answer to this one is (-5, 2)
Thanks
Found 2 solutions by lucky83, rapaljer:
Answer by lucky83(12) (Show Source): You can put this solution on YOUR website!
the equation x^ - 12x + 35 was summited,i believe it was intended to be
x^2-12x+35
if that is the case then if factors out to be (x-7)(x-5)=0
so x=7 x=5
part two x^2 + 3x - 10 + 0.
if also can be factored without the quadradic equation
(x-2)(x+5)=0
x=2 x=-5
Answer by rapaljer(4671) (Show Source): You can put this solution on YOUR website!
To factor , you need to find two numbers whose product is +35 and whose sum is -12. The fact that the product of the numbers is positive, means that the numbers must be the same sign, and the fact that they must add up to a negative 12 means that they must both be negative. So the answer is (x-7)(x-5).

See my explanations in my lesson plans entitled Products of Binomials by F OI L and also my lesson plan about Factoring Trinomials. The first of these is also listed on my own website, as well as the lesson plan on algebra.com under "Math in Living Color."

For the second problem, you probably meant . As an extra reference on this see my lesson plan on algebra.com on Solving Quadratic Equations, also on my own website as well.

The first step is to factor:

Set each factor equal to zero:
x+ 5 = 0
x= -5

x-2 = 0
x= 2

However, it is best to NOT use parentheses, since this means a LOT of other things of which this is NOT one of them. (-5,2) is NOT correct notation.

R^2 at SCC
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