SOLUTION: Find the value of m so that dividing x^4-mx^3-2x^2+(3m-5)x+m by (x-m) gives a remainder of 5.

SOLUTION: Find the value of m so that dividing x^4-mx^3-2x^2+(3m-5)x+m by (x-m) gives a remainder of 5.

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Question 933555: Find the value of m so that dividing x^4-mx^3-2x^2+(3m-5)x+m by (x-m) gives a remainder of 5.
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
x^4-mx^3-2x^2+(3m-5)x+m by (x-m) gives a remainder of 5.
substitute x=m
m^4-m^4-2m^2+3m^2-5m+m
m^2-4m =5
m^2-4m-5=0
m^2--5m+m-5=0
m(m-5)+1(m-5)=0
(m-5)(m+1)=0
m=5 OR 1
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