SOLUTION: {{{15x^2+31x+2 what is the factor of this equation

Question 925335: AMP Parsing Error of []: Invalid expression '': syntax error at /home/ichudov/project_locations/algebra.com/templates/Algebra/Expression.pm line 203. . 15x^2+31x+2 what is the factor of this equation
Found 2 solutions by ewatrrr, TimothyLamb:
Answer by ewatrrr(24785) (Show Source): You can put this solution on YOUR website!
15x^2+31x+2 = 0
(15x + 1)(x + 2) = 0)
F First terms
O Outside terms
I Inside terms
L Last terms

Answer by TimothyLamb(4379) (Show Source): You can put this solution on YOUR website!
15x^2 + 31x + 2 = 0
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the above quadratic equation is in standard form, with a=15, b=31 and c=2
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to solve the quadratic equation, by using the quadratic formula, copy and paste this:
15 31 2
into this solver: https://sooeet.com/math/quadratic-equation-solver.php
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the quadratic has two real roots at:
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x = -0.066666666 = -2/30
x = -2
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by factoring:
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15xx + 31x + 2 = 0
(15xx + 31x + 2 = 0)/15
xx + (31/15)x + 2/15 = 0
xx + (2/2)(31/15)x + (2/2)(2/15) = 0
xx + (62/30)x + (4/30) = 0
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factoring:
(x + 2/30)(x + 60/30) = 0
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check the above factoring for correctness:
xx + (60/30)x + (2/30)x + (2/30)(60/30) = 0
xx + (62/30)x + (2*60/30*30) = 0
xx + (62/30)x + (2*2/30) = 0
xx + (62/30)x + (4/30) = 0
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simplify the factoring:
(x + 2/30)(x + 2) = 0
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two real roots:
x = -2/30
x = -2
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https://sooeet.com/math/quadratic-formula-solver.php
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