SOLUTION: Factor each of the following polynomials completly
14x^2 - 20x + 6
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Question 92350: Factor each of the following polynomials completly
14x^2 - 20x + 6
Answer by prabhjyot(165) (Show Source): You can put this solution on YOUR website!
Compare above equation with standard quad equation
we get
a = 14
b = -20
c = 6
Discriminant: =
Discriminant (64) is greater than zero. The equation has two solutions.
or
or
x1,2 = (20 ± 8) / 2*14
or
x1 = 28 / 28 = 1
x2 = 12 / 28 = 3/7
or
x1,2 = 1, 0.428
Equation factored:
14(x-1)(x-0.428)
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