SOLUTION: Factor each of the following polynomials completly 14x^2 - 20x + 6

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Question 92350: Factor each of the following polynomials completly
14x^2 - 20x + 6

Answer by prabhjyot(165)   (Show Source): You can put this solution on YOUR website!

Compare above equation with standard quad equation
we get
a = 14
b = -20
c = 6

Discriminant: =
Discriminant (64) is greater than zero. The equation has two solutions.

or

or
x1,2 = (20 ± 8) / 2*14
or
x1 = 28 / 28 = 1
x2 = 12 / 28 = 3/7
or
x1,2 = 1, 0.428
Equation factored:
14(x-1)(x-0.428)

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