SOLUTION: products of binominals. (3x-4)(6x+2) first the 3x(6x) then 3x(2) 2nd -4(6x) then -4(2) to get =18x^2+6x-24x-8 then the 6x(3x) then 6x(-4) next 2(3x) and 2(-4) =18x^2-24x+6x

Question 92208: products of binominals.
(3x-4)(6x+2)
first the 3x(6x) then 3x(2) 2nd -4(6x) then -4(2) to get =18x^2+6x-24x-8
then the 6x(3x) then 6x(-4) next 2(3x) and 2(-4) =18x^2-24x+6x-8 i get lost at this point. this problem from a review sheet i have not from a book.
do i simplify 18x^2-24x+6x-8? do i -24x+6x=-18x
then i am left with 18x^2-18x-8 is this correct?

Answer by jim_thompson5910(35256) (Show Source): You can put this solution on YOUR website!
Start with the given expression

When you FOIL, you multiply the terms in this order:
F-First (i.e. you multiply the first terms in each parenthesis which in this case are and )
O-Outer (i.e. you multiply the outer terms in each parenthesis which in this case are and )
I-Inner (i.e. you multiply the inner terms in each parenthesis which in this case are and )
L-Last (i.e. you multiply the last terms in each parenthesis which in this case are and )

So lets multiply the first terms:
multiply and to get

So lets multiply the outer terms:
multiply and to get

So lets multiply the inner terms:
multiply and to get

So lets multiply the last terms:
multiply and to get

Now lets put all the multiplied terms together

Now combine like terms

So the expression

FOILs to:

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